Programming Language/C, C++
[프로그래머스][Lv. 2] 행렬의 곱셈 C++ 풀이
myungsup1250
2022. 5. 3. 23:22
https://programmers.co.kr/learn/courses/30/lessons/12949
코딩테스트 연습 - 행렬의 곱셈
[[2, 3, 2], [4, 2, 4], [3, 1, 4]] [[5, 4, 3], [2, 4, 1], [3, 1, 1]] [[22, 22, 11], [36, 28, 18], [29, 20, 14]]
programmers.co.kr
풀이는 추후에 차차 올리도록 하겠습니다...
그냥 우리가 아는 행렬의 곱셈을 구현하면 됩니다.
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#include <vector>
using namespace std;
int arr1row = -1, arr1col = -1, arr2col = -1;
int calMatrix(int i, int j, vector<vector<int>>& arr1, vector<vector<int>>& arr2) {
int result = 0;
for (int k = 0; k < arr1col; k++) {
result += arr1[i][k] * arr2[k][j];
}
return result;
}
vector<vector<int>> solution(vector<vector<int>> arr1, vector<vector<int>> arr2) {
vector<vector<int>> answer;
arr1row = arr1.size(), arr1col = (*arr1.begin()).size(), arr2col = (*arr2.begin()).size();
for (int i = 0; i < arr1row; i++) {
answer.push_back(vector<int>());
for (int j = 0; j < arr2col; j++) {
answer[i].push_back(0);
}
}
for (int i = 0; i < arr1row; i++) {
for (int j = 0; j < arr2col; j++) {
answer[i][j] = calMatrix(i, j, arr1, arr2);
}
}
return answer;
}
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